Question

Arcsin(-1) + arccos 1 + arctg(- корень_с_3/3) + arcctg(- корень_с_3)

Answer 1

$arcsin(-1)+arccos 1+arctg(-\frac{\sqrt3}{3})+arcctg(-\sqrt3)=\\\\=-arcsin1+0-arctg\frac{\sqrt3}{3}-arcctg\sqrt3=\\\\=-\frac{\pi}{2}-\frac{\pi}{6}-\frac{\pi}{6}=\frac{\pi}{2}-\frac{\pi}{3}=\frac{\pi}{6}$