<span>2x^2-3x+104=-3x^2-48x+4
</span>
<span>2x^2-3x+104+3x^2+48x-4 =0
5x^2 + 45x + 100 = 0 / : 5
x^2 + 9x + 20 = 0
D = 9^2 - 4*1*20 = 81 - 80 = 1
VD = V1 = 1
x1 = -9 +1 / 2 = -8/2 = -4
x2 = -9 - 1 / 2 = - 10/2 = -5
</span>
Я решала у меня 0 получился в уравнении
Y'=(3-7x)^5=5*(3-7x)*(3-7x)'=5*(3-7x)*7=35*(3-7x)
2sin2x*cosx=sin2x
sin2x(cosx-1/2)=0
sin2x=0 or cosx=1/2
2x=pi*k, k in Integers or x=+-pi/6+2pi*n, n in Integers
x=pi/2*k, k in integers or x=+-pi/6+2pi*n, n in Integers