Question

Решить неравенстов (5/8)^(3x-7)<=(8/5)^(7x-3)

Answer 1

$\left(\dfrac{5}{8}\right)^{3x-7}\leq\left(\dfrac{8}{5}\right)^{7x-3}\\ \left(\dfrac{5}{8}\right)^{3x-7}\leq\left(\dfrac{5}{8}\right)^{-7x+3}\\ 3x-7\geq-7x+3\\ 10x\geq10\\ x\geq1$

Answer 2

(5/8)^(3x-7)=(8/5)^(7x-3)
(5/8)^3х-7=(5/8)^(-7х+3)
3х-7= -7х+3
3х+7х=3+7
10х=10
х=10/10
х=1