Question

Помогите решить пожалуйста
.........

Answer 1

1) 
28в⁶/с³ * с⁵/84в⁶ = с²*в⁶/3в⁶ = с²/3,

2)
14р⁴/q⁶ * q⁵/56р⁴ = 1/4q,

3)
30х²у : 72ху/z = 30х²у * z/72ху = 5хz/12,

4)
45а³в * с²/30а⁴в = 3с²/2а,

5)
(3х+6)/(х+3) * (х²-9)/(х²-4) =
= 3*(х+2)/(х+3) * (х-3)(х+3)/(х-2)(х+2) =
= 3*(х-3)/(х-2),

6)
(3а-9)/(а+2) : (а²-9)/(а²-4) =
= (3а-9)/(а+2) * (а²-4)/(а²-9) =
= 3*(а-3)/(а+2) : (а-3)(а+3)/(а-2(а+2) = 
= 3*(а-2)/(а+3),

7)
(2а-в)/а * (а/(2а-в) + а/в)= 
= (2а-в)/а * а/(2а-в) + (2а-в)/а * а/в = 
= 1 + (2а-в)/в = 
= в/в + (2а-в)/в =
= (в + 2а - в)/в = 
= 2а/в,

8)
(3х+у)/у * (у/х - 3у/(3х+у) = 
= (3х+у)/у * у/х - (3х+у)/у * 3у/(3х+у) =
= (3х+у)/у - (3ху+у²-3ху)/(3х+у)х = 
= у²/ху = у/х

Answer 2

$1) \frac{28b^6c^5}{84b^6c^3} = \frac{b^{6-6}c^{5-3}}{3} = \frac{c^2}{3} \\ 2) \frac{14p^4q^5}{56p^4q^6} = \frac{p^{4-4}}{4q^{6-5}} = \frac{1}{4q} \\ 3) \frac{30x^2yz}{72xy} = \frac{5xz}{12} \\ 4) \frac{45a^3bc^2}{30a^4b} = \frac{3c^2}{2a} \\ 5) \frac{3(x+2)(x-3)(x+3)}{(x+3)(x-2)(x+2)} = \frac{3x-9}{x-2} \\ 6) \frac{3(a-3)(a-2)(a+2)}{(a-3)(a+3)(a+2)} = \frac{3a-6}{a+3} \\ 7) \frac{2a-b}{a} \frac{ab+2a^2-ab}{(2a-b)b} = \frac{2a^2}{ab} = \frac{2a}{b}$$8) \frac{3x+y}{y} \frac{3xy+y^2-3xy}{(3x+y)x} = \frac{y^2}{xy} = \frac{y}{x}$