<span>(-СН2-СН2-)n
Mr(C2H4)= 28г
n=Mr</span>(-СН2-СН2-)n / Mr (C2H4)
1) n= <span>19600/28=700
2) n= </span><span>16520 / 28 = 590
n - ступінь полімеризації </span>
<span>2NaNO3+C=2NaNO2+CO2
![2Na^{+1}N^{+5}O_3^{-2}+C^0=2Na^{+1}N^{+3}O_2^{-2}+C^{+4}O_2^{-2}](https://tex.z-dn.net/?f=2Na%5E%7B%2B1%7DN%5E%7B%2B5%7DO_3%5E%7B-2%7D%2BC%5E0%3D2Na%5E%7B%2B1%7DN%5E%7B%2B3%7DO_2%5E%7B-2%7D%2BC%5E%7B%2B4%7DO_2%5E%7B-2%7D)
![C^0-4e^-=C^{+4}](https://tex.z-dn.net/?f=C%5E0-4e%5E-%3DC%5E%7B%2B4%7D)
·1 восстановитель
![N^{+5}+2e^-=N^{+3}](https://tex.z-dn.net/?f=N%5E%7B%2B5%7D%2B2e%5E-%3DN%5E%7B%2B3%7D)
·2 окислитель
P2O3 + O2=P2O5
![P_2^{+3}O_3^{-2}+O_2^0=P_2^{+5}O_5^{-2}](https://tex.z-dn.net/?f=P_2%5E%7B%2B3%7DO_3%5E%7B-2%7D%2BO_2%5E0%3DP_2%5E%7B%2B5%7DO_5%5E%7B-2%7D)
![P^{+3}-2e^-=P^{+5}](https://tex.z-dn.net/?f=P%5E%7B%2B3%7D-2e%5E-%3DP%5E%7B%2B5%7D)
</span><span><span>·2 восстановитель
</span>
![O_2^0+4e^-=2O^{2-}](https://tex.z-dn.net/?f=O_2%5E0%2B4e%5E-%3D2O%5E%7B2-%7D)
</span><span><span>·1 окислитель</span>
</span>
5CH3-C(CH3)=CH2 +8KMnO4 +12H2SO4 -> 5CH3 -CO-CH3 +5CO2 +8MnSO4 +4K2SO4+17H2O
C(0) -2e -> C(+2)
C(-2) -6e -> C(+4) - 8e | 5-ок-ние; в-ль
Mn(+7) +5e -> Mn(+2) +5e | 8-в-ние;ок-ль
<span>6CH4 + 4O2 = C2H2 + 8H2 + 3CO + СО2 + 3Н2О
</span><span>С2Н2+Н2О=СН3СОН
(</span>CH3CHO = CH3COOH)---не хватает этой стадии
CH3COOH + CH3OH =CH3COOCH3
<span>CH3COOH + NH3 = CH3COONH4
</span><span>CH3COOH + CH3OH= CH3COOCH3</span>
Решение
600 мл = 0,6 л
n(Mg(OH)2) = 0.6 л*0,07 моль/л = 0,042 моль
M(Mg(OH)2) = 58 г/моль
m(Mg(OH)2) = n*M = 0,042 моль*58 г/моль = 2,436 г
Ответ: 2,436 г