<span>f(x)=2x^3-3x^2-12x+1
</span>f⁾(x)=(2x^3-3x^2-12x+1)⁾ =2*3*x²-3*2*x-12*1+0=6x²-6x-12
6x²-6x-12=0 сократим на 6
x²-x-2=0
D=1+8=9
x₁=(1+3)/2=2
x₂=(1-3)/2=-1
X2-3x+2=0
x1+x2=-b/a=3
x1*x2=c/a=2
x1=1
x2=2
(3х²+9х-5)-(7х²-6х+2)=7-2х-4х²
3х²+9х-5-7х²+6х-2-7+2х+4х²=0
17х-14=0
17х=14
Х=14/17
-12x+3xy-2(x+3xy)=-12x+3xy-2x-6xy=-14x-3xy
а) 10x-3xy=x(10-3y)
б) -14x+9xy=x(-14+9y)=x(9y-14)
в) -10x+9xy=x(-10+9y)=x(9y-10)
г) -14x-3xy=-x(14+3y)
2. 10x-5=6(8x+3)-5x
10x-5=48x+18-5x
10x-48x+5x=18+5
-33x=23
x=-23/33
3. а) 8xa+4xb=4x(2a+b)
б) 18xy^3+12x^2y=6xy(3y^2+2x)