25m²-10mn³+n⁶ = (5m - n³)² = (5m-n³)(5m-n³)<span>
4n³ ₓ 0,3n⁵ = 1,2</span>³⁺⁵ = 1,2n⁸<span>
x(2y-3x)-y(2x-4y) = 2xy - 3x</span>² - 2xy + 4y² = 4y² - 3x²<span>
(xy-3y)+(xa-3a) = y</span>(x-3) + a(x-3) = (x-3)(y+a)
<span>
(x-1)(x+1)-x(x-2)=0
x</span>² - 1- x² + 2x= 0
<span> 2x = 1
x = 1 : 2
x = 0,5
(x²-1²) </span>· (x-1)(x+1) = (x²-1²) · (x²-1²) = (x²-1)²
Ответ по заданному выражению: t^-5
18_03_09_Задание № 1:
Вычислите (2−1)(2+1)(2^2+1)(2^4+1)(2^8+1)−2^16
РЕШЕНИЕ: (2−1)(2+1)(2^2+1)(2^4+1)(2^8+1)−2^16=(2^2−1^2)(2^2+1)(2^4+1)(2^8+1)−2^16=(2^2−1)(2^2+1)(2^4+1)(2^8+1)−2^16=(2^4−1^2)(2^4+1)(2^8+1)−2^16=(2^4−1)(2^4+1)(2^8+1)−2^16=(2^8−1^2)(2^8+1)−2^16=(2^8−1)(2^8+1)−2^16=2^16−1^2−2^16=-1
ОТВЕТ: -1