<span>w(C)=81,8% )</span>w(H=18,2% Dh=22 найти Сx Hy
<span>Mr( Сx Hy )=2*22 =44</span>
<span>n(C)=W(C)*Mr( Сx Hy )</span>
<span> Ar( C )*100% </span>
<span>n(C)=81,8*44</span>
<span> 12*100%</span>
n(C)=3
n(H)=w(H)*Mr( Сx Hy )
Ar( H )*100%
n(H)= 8
Ответ:С2Р8-пропан
BaCl2 + Na2SO4 = BaSO4↓ + 2NaCl
Ba2+ + 2Cl- + 2Na+ + SO4 2- = BaSO4↓ + 2Na+ + 2Cl-
Ba2+ + SO4 2- = BaSO4↓
Ca(NO3)2 + Na2CO3 = CaCO3↓ + 2NaNO3
Ca2+ + 2NO3- + 2Na+ + CO3 2- = CaCO3↓ + 2Na+ + 2NO3-
Ca2+ + CO3 2- = CaCO3↓
2NaOH + MgCl2 = 2NaCl + Mg(OH)2↓
2Na+ + 2OH- + Mg2+ + 2Cl- = 2Na+ + 2Cl- + Mg(OH)2↓
Mg2+ + 2OH- = Mg(OH)2↓
FeCl3 + 3NaOH = Fe(OH)3↓ + 3NaCl
Fe3+ + 3Cl- + 3Na+ + 3OH- = Fe(OH)3↓ + 3Na+ + 3Cl-
Fe 3+ + 3OH- = Fe(OH)3↓
Дано:
m(Са(ОН)2)(р-ра)=50г
w(Ca(OH)2)=20%
Найти:
V(газа)=?