Тут же просто перемножить скобку на скобку
x^{2}+xy-zx-xy-y^{2}+yz-zx-yz+z^{2]=x^{2}-2zx-y^{2}+z^{2}
xy и -xy взаимоуничтожаем yz и-yzвзаимоуничтожаем
2х²-5х-3=0
Решаем через нахождение D
D=25+24=49
√D=7
x1=(5+7)/4=3
x2=(5-7)/4=-0,5
Ответ: Б. 3
a) 15x^4+3x^2+1
б) 3x^5-1/sqrt(x)
в) -14(3-2x)^6
г) -3sin3x
д) 2(x-3)x^3+3(x-3)^2*x^2=(x-3)x^2(2x+3x-9)=(x-3)(5x-9)
е) (2(x+2)-(2x-3))/(x+2)^2=7/(x+2)^2
2) f'(x)=10x^8-90x^9
f''(x)=80x^7-810x^8
f''(-1)=-80-810=-890
3)f'=2x+3
f''=2
<span>√(54/125</span><span><span>) = <span>√(6*9/5*25</span><span><span>) = </span></span><span>3/5 √(6/5</span><span><span>) </span></span>
</span></span>
<span>√(248/128</span><span><span>) = <span>√(124/64</span><span><span>) = </span></span><span><span><span>√(31/16</span><span><span>) = </span></span></span></span>1/4 <span><span><span>√(31</span><span><span>) </span></span></span></span>
</span></span>
<span>√(13/32</span><span><span>) = <span>√(13/2*16</span><span><span>) = </span></span><span>1/4 √(13/2</span><span><span>)</span></span>
</span></span>
<span>√(17/81</span><span><span>) = 1/9 <span>√(17</span><span><span>) </span></span>
</span></span>
1) 2\7 - 1\14 = 4\14 - 1\14 = 3\14
2) 3.5 - 17.5 = - 14
3) 3\14 * (- 14) = - 3
ОТВЕТ: минус 3