Cos(2Pi)Cos(2x)+Sin(2Pi)Sin(2x)+3(sinPi*cosx-cosPi*sinx)=
=1*cos2x+0*sin2x+3(0*cosx-(-1)sinx)=cos2x+3sinx=1-2Sin^2(x)+3sinx=0
sinx=t
-2t^2+3t+1=0
<span>2t^2-3t-1=0
</span>D=9+4*2*1=15
t1=(3-√15)/4
t2=(3+√15)/4 не подходит т.к. sinx д.б. от -1 до 1
sinx=<span>(3-√15)/4
x=arcsin(</span><span>(3-√15)/4</span>)
1. x' = 2t/(1+t^2); y' = 1/(1+t^2)
y'/x' = 1/2t
y'(t=1/2) = 1
2. x'=3; y'=2t
y'(t=3) = 2*3/3=2
3. x'(t) = (2 - 2t) / 2sqrt(2t-t^2) = (1 - t) / sqrt(2t - t^2)
y'(t) = 1 / sqrt(1 - (t-1)^2) = 1 / sqrt(2t - t^2)
y'(t=2/3) = 1 / (1 - 2/3) = 3
x^2+y^2=4
y^2 = 4- x^2
y= sqrt ( 4-x^2)
4-x^2 <span> ≥ 0</span>
<span>(2-x) (x+2) <span> ≥ 0 </span></span>
<span><span>x = 2, -2</span></span>
Ответ : х принадлежит [ -2; 2]
Х=3
y= -2
Значение выражения 1225
