![\dfrac{(x-5)(2x^2-4x+2)}{x+3} \leq 0 \\ \dfrac{2(x-5)(x-1)^2}{x+3} \leq 0](https://tex.z-dn.net/?f=+%5Cdfrac%7B%28x-5%29%282x%5E2-4x%2B2%29%7D%7Bx%2B3%7D+%5Cleq+0+%5C%5C++%5Cdfrac%7B2%28x-5%29%28x-1%29%5E2%7D%7Bx%2B3%7D+%5Cleq+0+)
Применяем метод интервалов:
___+___(-3)___-___1____-____5___+___
![x \in (-3; 5]](https://tex.z-dn.net/?f=x+%5Cin+%28-3%3B+5%5D)
Целые решения: -2; -1; 0; 1; 2; 3; 4; 5
5^x*5^2+11*5^x=180
5^x(25+11)=180
5^x=180/36
5^x=5
x=1
1)(4+2)×2=12
2)(4+3)×2=14
3)(5+3)×2=16
4)(14+26)×2=80
1. b1=4
b4=108
bn=b1*q^(n-1)
b4=b1*q³=4*q³=108;
q³=108/4=27;
q=3
b2=b1*q=4*3=12
b3=b1*q²=4*9=36