Х+(1\х)=8
(х+(1\х))²=х²+2·х·1\х+(1\х)²=((х²+(1\х)²)+2=8+2=10
x+y+z=4
2xy-z^2=16
z=4-(x+y)
2xy-16+8(x+y)-(x+y)^2=16
2xy-16+8(x+y)-x^2-2xy-y^2=16
-x^2-y^2+8(x+y)=32
(-x^2+8x-16)+(-y^2+8y-16)=0
-(x-4)^2-(y-4)^2=0
-(x-4)^2=(y-4)^2
x-4=0
y-4=0
x=4
y=4
z=-4
x+y+2z=0
Ответ:
<span>6a+7b/3a−4b
</span>6*1,2+7*5,4/3*1,2-4*5,4
7,2+37,8/3,6-21,6
45/-8
-2,5
217²-216²=(217+216)(217-216)=433*1=433
1) х(а-2)=(а-2)(а+2)
х=(а-2)(а+2)/(а-2)
x=(a+2)
2) х(с-d)=5(c-d)
x=5(c-d)/(c-d)
x=5
3) x(a-b)=(a-b)(a+b)
x=(a-b)(a+b)/(a-b)
x=(a+b)