√(3-√6) + √(2-√6)= √(√9-√6) + √(√4-√6)= √(√3(√3-√2)) + √(√2(√2-√3))=√(-√3(√2-√3)) + √(√2(√2-√3))= √(√2-√3)*(√2-√3)=√(√2-√3)²=модуль(√2-√3)=√3-√2 , <em>так как √3>√2. (√3-√2)>0.</em>
![25x^2-3ax+1=0\\ D \ \textless \ 0\\ D = 9a^2-100\\ 9a^2-100 \ \textless \ 0\\ (3a-10)(3a+10) \ \textless \ 0\\ ](https://tex.z-dn.net/?f=25x%5E2-3ax%2B1%3D0%5C%5C%0AD+%5C+%5Ctextless+%5C++0%5C%5C%0AD+%3D+9a%5E2-100%5C%5C%0A9a%5E2-100+%5C+%5Ctextless+%5C++0%5C%5C%0A%283a-10%29%283a%2B10%29+%5C+%5Ctextless+%5C++0%5C%5C%0A)
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................(-10/3).......................(10/3)................
![a \in (-\frac{10}{3}; \frac{10}{3})\\](https://tex.z-dn.net/?f=a+%5Cin+%28-%5Cfrac%7B10%7D%7B3%7D%3B+%5Cfrac%7B10%7D%7B3%7D%29%5C%5C)