Question

(6-x)(x^2 -8x+12)/x^3-36x >либо=0 заранее спасибо!

Answer 1

$(6 - x) \times ( {x}^{2} - 8x + 12) \\ \div {x}^{3} - 36x \geqslant 0$
6x²-48x+72-x³+8x²-12x
(14x²-60x+60)
-------------------- ≥o
x³-36

[x≠0 [x≠-6
[x³-36x≠0 [x(x²-36)≠0 [x²≠36 [x≠6
[x³-36x>0 [x(x²-36)>0 [x>0
[x²-36>0 [ x<6 [x>6
[x>-6 [x<-6