a1 + 9d = 40
a1 + d = 8
(отнимаем от 1 го второе)
8d = 32
d = 4
a1 = 4
a12 = a1 + 11d = 4+ 11*4 = 48
S12 = (a1+a12)*12/2 = (a1+a12)*6 = (4 + 48)*6 = 312
1. a) ...=b(2a-3)-2a(b-2)/2ab=2ab-3b-2ab+4a=-3b+4a
б) ...=(a+3)×3(a+3)×96a^4/8a(a+3)=3(a+3)×12a^3=3a+9×12a^3
в) ...=(x-y)(x+y)/2x(x+y)=x-y/2x