Ca+2HCL=H2+CaCL2
m HCL=50*0/1=5 г
n HCl=5/36.5=0.14 моль
n Ca=0.14/2=0.07 моль
m Ca=40*0.07=2.8 г
<span>Метод Шееле:
</span>MnO2<span> + 4HCl → MnCl</span>2<span> + Cl</span>2↑ + 2H2O
<span>Метод Дикона
</span>4HCl + O2<span> → 2H</span>2O + 2Cl<span>2
</span>
2KMnO4<span> + 16HCl → 2KCl + 2MnCl</span>2<span> + 5Cl</span>2↑ +8H2<span>O</span>
Pb(H3CCOO)2 + CaOCl2 + H2O = PbO2 + CaCl2 + 2H3CCOOH:
Pb2+ -2e- + 2H2O = PbO2 + 4H+ | 2 | 2 | 1 |
(ClO)- +2e- + 2H+ = Cl- + H2O | 2 | | 1 |;
Pb2+ + (ClO)- + H2O = PbO2 + Cl- + 2H+.
М(CaCO3)=100 М(СаО)=56
х=500*56\100=280
2Al+3Cl=3AlCl3
2Al+H2O=2Al(OH)3+3H2⬆
2Al+6HCl3=2AlCl+3H2⬆