1. H2SO4+Ba(OH)2=BaSO4+2H2O
M(H2)=n*M=V/Vm*M=67,2/22,4*2=6 г
Ответ:6 г.
<span>1.</span>
<span>а) 2HNО3 + 2LiOH2<span> </span><span>-»</span> LiNО3 + 2Н2О </span>
<span><span>в) 4Fe + 3Н2О </span></span><span> </span><span>-»2</span><span>Fe2О3 + 3Н2</span>
<span>г)3К2О + Р2О5 -> 2К3РО4 </span>
<span><span>д) K2SО4 + 2AgNО3 <span> </span><span>-></span>Ag2SО4 + 2KNO3</span></span>
<span><span>2.</span></span>
<span>а)K2S+Pb(NO3)2</span><span> </span><span>->PbS+2KNO3</span>
<span>б)4Al+3O2<span> </span><span>->2Al2O3</span></span>
<span><span>в)Н2СО3<span> </span><span>->Н2О+СО2 стрелочка вверх(показатель газа)</span></span></span>