2 ответа:
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<span> 2sin2x+3tgx=5
</span>
3tg³x-3tg²x-5tg²x+7tgx-5=0
3tg³x-3tg²x-2tg²x+2tgx+5tgx-5=0
3tg³x ( tgx-1)-2tgx (tgx-1) +5(tgx-1)=0
<span>(tgx-1)(3tg</span>²x-2tgx+5)=0
<span>tgx=1
</span>[tex]x1= π/4 +πk=π/4(4+k)
<span>k </span>∈ Z
3tg²x-2tgx+5≠0 (D <0 ) ∅
OTVET: X=π/4(4k+1 ) , k ∈ Z
</span>
3tg³x-3tg²x-5tg²x+7tgx-5=0
3tg³x-3tg²x-2tg²x+2tgx+5tgx-5=0
3tg³x ( tgx-1)-2tgx (tgx-1) +5(tgx-1)=0
<span>(tgx-1)(3tg</span>²x-2tgx+5)=0
<span>tgx=1
</span>[tex]x1= π/4 +πk=π/4(4+k)
<span>k </span>∈ Z
3tg²x-2tgx+5≠0 (D <0 ) ∅
OTVET: X=π/4(4k+1 ) , k ∈ Z