1) (1/32)^(2x) >= sqrt(0.125)
0.5^(5*2x)>=0.5^(3/2)
10x <= 3/2
x<=3/20
x<=0.15
2) log(1/3, 5x-1) >=2
ОДЗ: 5x-1>0, x>0.2
log(1/3, 5x-1) >= log(1/3, 1/9)
5x-1 <= 1/9
x<=2/9
С учетом ОДЗ, 0.2 < x <= 2/9
18-3x= 0
3x=18-0
3x=18
X=18:3
X=6
Ответ:6
1. 802–(414–82)+(395–109)=756
1)414–82=332
2)395–109=286
3)802–332=470
4)470+286=756
2.(119+78)–(540–509)+405=571
1)119+78=197
2)540–509=31
3)197-31=166
4)166+405=571
3. 3•(421-325):2=144
1)421-325=96
2)3•96=288
3)288:2=144
4.980-(745-199):2=217
1)745-199=546
2)980-546=434
3)434:2=217