sin4a/cos6x=cos2a/sin4a
sin^2(4a)=cos6a*cos2a=0.5(cos8a+cos4a)
пусть 4a=y
2sin^2y=cos2y+cosy
2(1-cos^2y)=cos^2y-sin^2y+cosy
2-2cos^2y-cos^2y+sin^2y-cosy=0
2-3cos^2y+(1-cos^2y)-cosy=0
3-4cos^2y-cosy=0
пусть cosy=t
3-4t^2-t=0
D=1^2-4(-4)*3=49
t1=(1+7)/(-8)=-1; cos4x=-1; 4x=pi+2pil; x=pi/4+pik/2
t2=(1-7)/(-8)=3/4; cos4x=3/4; 4x=+-arcc0s(3/4)+2pik; x=+-0.25 arccos(3/4)+pik/2
<span>4sin5x+2=0</span>
sin5x=-1/2
5x=(-1)^(n+1) * arcsin(1/2)+πn, n∈Z
5x=(-1)^(n+1) * π/6+πn, n∈Z
x=(-1)^(n+1) * π/30+πn/5, n∈Z
x=(-1)^(n+1) *6(градусов) + 16(градусов)*n, n∈Z
при n=-1 х=-10(градусов)
при n=0 х=-6(градусов)
при n=1 x=22(градуса)
1) 3/7t-5/7t=1-3
-2/7t=-2
t=7
2) во втором где равно?
3)2/5z=10
z=25