Sin4x-sin(π/2-6x)=2*sin(4x-(π/2-6x))/2
*cos(4x+π/2-6x)/2=
2*sin(4x-π/2+6x)/2*cos((π/2-2x)/2=
2*sin(10x/2-π/2:2)*cos(π/2:2-2x:2)=
2*sin(5x-π/4)*cos(π/4-x)
Решение прицеплено в картинке.
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1. 25х²=16
25х² - 16 = 0
х² = -с/а
х² = 16/25
<u>х 1, 2 = +- 4/5</u>
<span>2. 7х²-3х=0</span>
7х² = 3х
х(7х - 3) = 0
<u>х1 = 0</u> или 7х-3 = 0
7х = 3
<u>х2 = 3/7</u>