Y'(x)= (x²+sin3x)'=
=(x²)'+(sin3x)'=
=2x+cos3x•(3x)'=
=2x+3cos3x
<span>1) x - y = 10
15 и 5; 20 и 10; 45 и 35.
2) x = 4y
4 и 1; 8 и 2; 12 и 3.
3) 2x</span>² <span>+ y = 20
1 и 18; 2 и 12; 3 и 2.
</span>
...............................
<span><span>ctg^2a-tg^2a=cos^2a/sin^2a-sin^2a/cos^2a=(cos^4a-sin^4a)/cos^2a*sin^2a=cos2a/(sinacosa)^2
(cos^2a-sin^2a)/(cos2a)/(sinacosa)^2=sin^2a*cos^2a</span></span>
y¹=(3*(x+3)-3x*1) /(x+3)² -7sinx=3/(x+3)²-7sinx