N=n*Nавогадро=1,5моль
6*10(23)моль=9*10(23)молекул
Mn (7+) + 1e ==> Mn (+6)
Mn (+7) + 3e ==> Mn (+4)
Марганец принял электроны и восстанавился
перманганат калия - это и есть окислитель
O(-2) -2e ==> O(0) | 2
Ответ:
Объяснение:
18,4 г Х л
2CH3OH + 3O2 = 2CO2 + 4H2O
n=2 моль n=3 моль
М=32 г/моль Vm=22,4 л/моль
m=64 г V = 67,2 л
18,4 г СН3ОН - Хл О2
64 г СН3ОН - 67,2 л О2
V(O2) = 18,4 * 67,2 / 64 = 19,32 л
Mg(NO3)2 + 2<span>NaOH </span>=<span> Mg(OH)</span>2 + 2NaNO<span>3
</span>Mg(OH)2 +<span> H</span>2SO4 =<span> MgSO</span>4 + 2H2<span>O
</span>MgSO4 +<span> Ba(NO</span>3)2 =<span> Mg(NO</span>3)2 +<span> BaSO</span><span>4
</span><span>2Mg(NO3)2 = 2MgO + 4NO2 + O<span>2 (ОВР)
![\left. \begin{array}{r} \mathrm{2O^{-2}-4e^{-}\to O_{2}^{0}} \\ \mathrm{N^{+5}+e^{-}\to N^{+4}} \end{array} \right|4 \left| \begin{array}{l} \mathrm{1-reducing\;agent} \\ \mathrm{4-oxidizing\;agent} \end{array} \right.](https://tex.z-dn.net/?f=%5Cleft.+%5Cbegin%7Barray%7D%7Br%7D+%5Cmathrm%7B2O%5E%7B-2%7D-4e%5E%7B-%7D%5Cto+O_%7B2%7D%5E%7B0%7D%7D+%5C%5C+%5Cmathrm%7BN%5E%7B%2B5%7D%2Be%5E%7B-%7D%5Cto+N%5E%7B%2B4%7D%7D+%5Cend%7Barray%7D+%5Cright%7C4+%5Cleft%7C+%5Cbegin%7Barray%7D%7Bl%7D+%5Cmathrm%7B1-reducing%5C%3Bagent%7D+%5C%5C+%5Cmathrm%7B4-oxidizing%5C%3Bagent%7D+%5Cend%7Barray%7D+%5Cright.)
</span></span>MgO +<span> C </span>=<span> Mg </span>+<span> CO (ОВР)
![\left. \begin{array}{r} \mathrm{C^{0}-2e^{-}\to C^{+2}} \\ \mathrm{Mg^{+2}+2e^{-}\to Mg^{0}} \end{array} \right|2 \left| \begin{array}{l} \mathrm{1-reducing\;agent} \\ \mathrm{1-oxidizing\;agent} \end{array} \right.](https://tex.z-dn.net/?f=%5Cleft.+%5Cbegin%7Barray%7D%7Br%7D+%5Cmathrm%7BC%5E%7B0%7D-2e%5E%7B-%7D%5Cto+C%5E%7B%2B2%7D%7D+%5C%5C+%5Cmathrm%7BMg%5E%7B%2B2%7D%2B2e%5E%7B-%7D%5Cto+Mg%5E%7B0%7D%7D+%5Cend%7Barray%7D+%5Cright%7C2+%5Cleft%7C+%5Cbegin%7Barray%7D%7Bl%7D+%5Cmathrm%7B1-reducing%5C%3Bagent%7D+%5C%5C+%5Cmathrm%7B1-oxidizing%5C%3Bagent%7D+%5Cend%7Barray%7D+%5Cright.)
</span><span>4Mg + 10HNO3 = 4Mg(NO3)2 + NH4NO3 + 3H2O (ОВР)
![\left. \begin{array}{r} \mathrm{Mg^{0}-2e^{-}\to Mg^{+2}} \\ \mathrm{N^{+5}+8e^{-}\to N^{-3}} \end{array} \right|8 \left| \begin{array}{l} \mathrm{4-reducing\;agent} \\ \mathrm{1-oxidizing\;agent} \end{array} \right.](https://tex.z-dn.net/?f=%5Cleft.+%5Cbegin%7Barray%7D%7Br%7D+%5Cmathrm%7BMg%5E%7B0%7D-2e%5E%7B-%7D%5Cto+Mg%5E%7B%2B2%7D%7D+%5C%5C+%5Cmathrm%7BN%5E%7B%2B5%7D%2B8e%5E%7B-%7D%5Cto+N%5E%7B-3%7D%7D+%5Cend%7Barray%7D+%5Cright%7C8+%5Cleft%7C+%5Cbegin%7Barray%7D%7Bl%7D+%5Cmathrm%7B4-reducing%5C%3Bagent%7D+%5C%5C+%5Cmathrm%7B1-oxidizing%5C%3Bagent%7D+%5Cend%7Barray%7D+%5Cright.)
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