(∛(4-√15))^x=1/(∛(4+√15))^x
(∛(4+√15))^x=a
a+1/a=8
a²-8a+1=0
D=64-4=60
a1=(8-2√15=4-√15⇒(∛(4+√15))^x=4-√15⇒x/3=-1⇒x=-3
a2=4+√15⇒(∛(4+√15))^x⇒x/3=1⇒x=3
Y=√(x*(3+x)(4-x))
x*(3+x)(4-x)≥0
x=0 x+3=0 x=-3 4-x=0 x=4
-∞______+______-3_____-______0_____+______4_______-______+∞
Ответ: x∈(-∞;-3]U[0;4].
11/6=1,83( должно быть вот так.)
2x-7=0
2x=7
x=7\2=3,5
7+x=0
x=-7
2x-7=7+x
2x-x=7+7
x=14
<span>1) с(х-3)-d(х-3) = (x-3)(c-d)
2) m(р-k)-(р-к) = (p-k)(m-1)
3) m(х-у)-n(у-х) = (x-y)(m+n)
4) х(2-х)+4(х-2) = (2-x)(x-4)
5) 4x(2x-y)-5y(y-2x) = (2x-y)(4x+5y)
6) (y+1)^2-4y(y+1) = (y+1)(y+1-4y) = (y+1)(1-3y)</span>