Исходя из формулы W=mp.в*100%./mp-pa
mp.в.=180*35/100=63 г
W(C):W(H):W(N) = 77,4/12 : 7,5/1 : 15,1/14 = 6:7:1
C6H5NH2 Анилин
М (KMnO4) = 158
M (Mn) = 55
Массовая доля Mn = (55 / 158) * 100% = 34,8 %
Mr(H2SO4) = 1*2 + 32 + 16*4 = 98
W(O) = Ar(O) * n / Mr(H2SO4) *100% = 16*4 / 98 *100% =65 %
Mr(HNO3) = 1 + 14 + 16*3 = 63
W(O)= Ar(O) * n / Mr(HNO3) *100% = 16*3 / 63 *100% = 76%
Mr(H3PO4) = 1*3 + 31 + 16*4 = 98
W(O)= Ar(O) * n / Mr(H3PO4) *100% = 16*4 / 98 *100% = 65%
Mr(NaOH) = 23+16+1 = 40
W(O) = Ar(O) * n / Mr(NaOH) *100% = 16*1/ 40 *100% = 40%
Ответ: NaOH