(х-4)(х+5)=х²+5х-4х-20=х<span>²+х-20</span>
Y'(x)=-3x^2-4x-3, y'(-2)=-7, y(-2)=10.
y-10=-7(x+2)=>y=-7x-4.
Ответ: y=-7x-4
3х+5y-6x-5y=21-27
-3x=-6
x=2
3*2+5y=21
5y=21-6
5y=15
<span>1) y=3
2) 3x+5*3=21
3x=6
x=2
</span>
<span><span>Решение. 3*(sin(x))^2-2*sin(2*x)+5*(cos(x))^2=2; (sin(x))^2-4*sin(x)*cos(x)+3*(cos(x))^2=0;
(tg(x))^2-4*tg(x)+3=0; tg(x1)=3; tg(x2)=1</span></span>