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Наверно 2 так как элементы находятся в одном периоде
Ba(OH)2 + Na2SO4 = BaSO4 + 2NaOHBa(2+) + SO4(2-) = BaSO4Ba(OH)2 + 2HNO3 = Ba(NO3)2 + 2H2OH(+) + OH(-) = H2OBa(OH)2 + CO2 = BaCO3 + H2OBa(2+) + 2OH(-) + CO2 = BaCO3 + H2OBa(OH)2 + FeCl2 = Fe(OH)2 + BaCl2Fe(2+) + 2OH(-) = Fe(OH)2
1_ CH3 CH3
| |
CH3-CH - CH-CH2-CH3
2_ J C2H5
| |
CH2-CH-CH-CH-CH2-CH2-CH2-CH2-CH2-CH3
|
CH3
3)
Br CH3
| |
CH2-CH-CH-CH3
|
CH3
4)
CH3 CH3 CL
| | |
CH3- C - C - CH-CH-CH2-CH2-CH2-CH3
| | |
CH3 CH3 CH3
<span>H2SO4 + CuO = CuSO4
+ H2O</span>
<span>
</span>
m — масса раствора
кислоты
<span>m(CuSO4)=8 г
</span>
<span>w(H2SO4)=60%
</span>
<u>m(H2SO4)=m*w/100
</u>
<span>M(CuSO4) =159,5 г/моль
</span>
<span>M(H2SO4)=98
г/моль
</span>
<span>
</span>
<span>m(CuSO4)/M(CuSO4) =
m(H2SO4)/M(H2SO4)</span>
<span>
</span>
<span>m(CuSO4)/M(CuSO4) =
m*w/(100*M(H2SO4))</span>
<span>
</span>
<span>m=m(CuSO4)*100*M(H2SO4)/(w*M(CuSO4))</span>
<span>
</span>
<span>m= 8*100*98/(60*159,5) = <span>8,19
г</span></span>