Question

6(0,7х+2)+1,4(3у+4) при х+у=5

Answer 1

6(0,7х+2)+1,4(3у+4) при х+у=5
6(0,7х+2)+1,4(3у+4)=4,2x+12+4,2y+5,6=4,2(x+y)+17,6=>
4,2*5+17,6=21+17,6=38,6