1). а). - н-гексан б). - 2-метил бутан в). - 2,2-диметил пропан г). - 2,2-диметил бутан
2). 2C2H6+7O2→4CO2+6H2O
C2H6→C2H4+H2→C2H2+H2
CH4+HONO2→CH3NO2+H2O
3). 29*3,39=98
0,1579*98=16
0,8421*98=82
82/12=7
C7H16
Неплохо было бы переворачивать фотографии!
дано
m(CxHy) = 8.4 g
m(CO2) = 26.4 g
m(H2O) = 10.8 g
D(возд) = 2.9
-------------------
CxHY-?
M(CxHy) = D(возд)*29 = 2.9 * 29 = 84 g/mol
n(C) = n(CO2) = m(CO2) / M(CO2) = 26.4 / 44 = 0.6 mol
n(H) = 2n(H2O) = 2(m(H2O) / M(H2O)) = 2*10.8 / 18 = 1.2 mol
n(C) : n(H) = 0.6 : 1.2 = 6 :12
C6H12
ответ C6H12
2NaOH+H2SO4=Na2SO4+2H2O
2Na⁺+2OH⁻+2H⁺+SO4²⁻=2Na⁺+SO4²⁻+2H2O
2OH⁻+2H⁺=2H2O - утворюється вода
Na2SO4+BaCl2=2NaCl+BaSO4↓
2Na⁺+SO4²⁻+Ba²⁺+2Cl⁻=2Na⁺+2Cl⁻+BaSO4↓
SO4²⁻+Ba²⁺=BaSO4↓ випадає білий осад
1.
CH3COONa+HCl= CH3COOH + NaCl
CH3COOH + C2H5OH = CH3COOC2H5 + H2O
CH3COOC2H5 + H2O = CH3COOH + C2H5OH
CH3COOH + NaOH = CH3COONa
2.
(1)2CH4--(t°=1500°C)--C2H2 + 3H2
(2)1)С2H2 + H2 = C2H4
2)C2H4 + HOH = C2H5OH
(3) 5C2H5OH + 4KMnO4 + 6H2SO4 = 5CH3-COOH + 4K2SO4+ 2MnSO4+11H2O
(4)CH3-COOH +Cl2=<span>CH2ClCOOH + HCl
</span>3. CH3-COOCH3 + H2O = CH3OH + CH3-COOH
CH3OH+[O] = CH3 - COH + H2O
CH3-COH+ 2Cu(OH)2 = CH3-COOH + 2CuOH + H2O