Question

Решите уравнение y' cosx - y sin x=2x, y(0)=0

Answer 1

y' cosx - y sin x=2x
(y*cosx)'= y'*cosx-y*sinx =>
y*cosx= ∫sin2xdx=$- \frac{1}{2}$*cos2x+C
$y=- \frac{1}{2} *\frac{\cos2x}{cosx} + \frac{C}{cosx}$