(4/3)^5x>81/256
(4/3)^5x> (3/4)^4
(3/4)^-5x.(3/4)^4
-5x>4, -5,0
x<-4/5
x<-0,8
x принадлежит (-∞;-0,8)
<em>sin2x+2√3cos²x-6sinx-6√3cosx=0;</em>
= (х-2)(х²+2х+4) / х+2 * (х+2)² / х²+2х+4 = (х-2)(х+2) = х²-4
=sin^2 A+2sin A cos A+cos^2 A +1-2sin A cos A= 1+1=2
4*a^3*b* 12*(ab^2)^3 * 3a = = 4*a^3*b * 12a^3*b^6 * 3a = = 4*12*3*a^3*a^3*a*b*b^6 = = 144a^(3 + 3 + 1) * b^(1 + 6) = = 144*a^7*b^7