(6/5)^-2≥(6/5)^4x-5
-2≥4x-5
4x≤-2+5
4x≤3
x≤0,75
x∈(-∞;0,75]
A₁ = 24; a₂ = 21.
d = a₂ - a₁ = 21 - 24 = -3
S₁₀ = 10·(2a₁ + 9d)/2 = 5(2a₁ + 9d) = 10a₁ + 45d = 10·24 + 45·(-3) = 105
Ответ: S₁₀ = 105.
А)(х-4у)(х+4у)=х²-16у²
(а+в)(а-в)=а²-в²
б)(6а+2)(6а-2)=36а²-4
в)(у^6-3х)(3х+^6)=у^12-9х²
г)(3х²-у³)(3х²+у³)=9х^4-у^6
^степень числа