Zn + 2 HCl = ZnCl2 + H2
по уравнению реакции n(Zn) = n(H2)
n(Zn) = m/M = 13 /65 = 0,2 моль (M(Zn) = 65 г/моль)
n(H2) = n(Zn) = 0,2 моль
<span><span>2<span>KOH</span></span>+<span>SO2</span> → <span>K2SO3</span>+<span>H2O
</span></span><span><span>Ca<span>(OH)</span>2</span>+<span>CO2</span> → <span>CaCO3</span>+<span>H2O
</span></span><span><span>Ba<span>(OH)</span>2</span>+<span>SO2</span> → <span>BaSO3</span>+<span>H2O
</span></span><span><span>2<span>NaOH</span></span>+<span>SO3</span> → <span>H2O</span>+<span>Na2SO<span>4
</span></span></span>
А).
1. n (C2H4Cl)=m/M=148,5÷99=1,5 моль
n (C2H4Cl)=n (C2H4)=1,5 моль
V (C2H4)=Vm×n=22,4×1,5=33,6л