1) √(10 1/12)= √(121/12)=√(11²/12)= 11/√12<span>
2) √(3 19/50) = </span>√(169 /50) =√(13²/50) =13/√50
(x+1)(x⁷-x⁶+x⁵-x⁴+x³-x²+x-1) = x⁸+x⁷-x⁷-x⁶+x⁶+x⁵-x⁵-x⁴+x⁴+x³-x³-x²+x²+x-x-1 = x⁸-1
-0,4а (2а^2+3)(5-3а^2) =
-0,4а (10а^2-6а^4+15-9а^2) =
-0,4а (-6а^4+а^2+15) =
<span>2,4а^5 - 0,4а^3 - 6а
</span>
5*x-5*3-2*(6-x)=-34
5x-15-2*(6-x)=-34
5x-15-(2*6-2*x)=-34
5x-15-(2*6-2*x)=-34
5x-15-(12-2x)=-34
5x-15-12+2x=-34
7x-15-12=-34
7x-27+-34
7x+-34+27
7x=_7
x=-7:7
x=-1