NH4Br + AgNO3 -> NH4NO3 + AgBr
NH4(+)+Br(-) + Ag(+)+NO3(-) -> NH4(+)+NO3(-) + AgBr
Ag(+)+Br(-) -> AgBr
<span>Это H3C-C≡C-CH(CH3)-CH3 (4-метилпентин-2):
</span><span>H3C-C≡C-CH(CH3)-CH3 + K2Cr2O7 + 4H2SO4 =
H3C-COOH (уксусная к-та) + H3C-CH(CH3)-COOH (диметилуксусная к-та,
2-метилпропановая к-та) + Cr2(SO4)3 + K2SO4 + 3H2O.</span>
<span>С<span>aCO</span></span>₂<span><span> ->
CaO + CO</span></span>₂
<span>CaO + 3C = CaC</span>₂<span> + CO</span>
<span>CaC</span>₂<span> + 2H</span>₂<span>O = Ca(OH)</span>₂<span> + C</span>₂<span>H</span>₂
<span><span>M(CaCO</span></span>₃<span><span> </span>чистого)= 25 кг * 0, 88 = 22кг</span>
<span><span>n(CaCO</span></span>₃<span><span>) = n(C</span></span>₂<span><span>H</span></span>₂<span><span>)= 22</span>кг/ 100кг/кмоль = 0.22 кмоль = 220 моль</span>
<span>V(C</span>₂<span>H</span>₂<span><span>)= 220 моль *22,4 л/моль = 4928 л = 4,928 м</span></span>³
Дано:
m(Na2CO3) = 218 r
V(H2O) = 1000 мл
t =20°C
Найти:
ω(Na2CO3)-?
m(H2O) = ρV = 1 г/мл*1000 мл = 1000 г
m(p-pa) = 1000 г + 218 г = 1218 г
ω(Na2CO3) = 218 г/1218 г = 0,179 или 17,9%
Ответ: 17,9%