6.
0.15^(1/5) * 9^(2/5) * 20^(11/5)=
=(0.05*3)^(1/5) * (3²)^(2/5) * 20^(11/5)=
= (1/20)^(1/5) * 3^(1/5) * 3^(4/5) * 20^(11/5)=
= (20⁻¹)^(1/5) * 20^(11/5) * 3^(1/5 + 4/5) =
= 20^(-1/5 + 11/5) * 3¹=
= 20² * 3 = 400*3 = 1200
Вот списывай удачиииииииииииииииии
B^2+2*3b+3^2- 6b= b^2+ 6b+9-6b= (6b и -6b сокращаем) =b^2+9