Y = 0
X^2 + 4X - 5 = 0
D = 16 - 4*1*(-5) = 16 + 20 = 36 ; V D = 6
X1 = ( - 4 + 6 ) \ 2 = 2 \ 2 = 1
X2 = ( - 10 ) \ 2 = ( - 5)
X = 0
Y = ( - 5 )
![8^7 - 2^{15} = (2^3)^7 - 2^{15} = 2^{21} - 2^{15} =](https://tex.z-dn.net/?f=8%5E7+-+2%5E%7B15%7D+%3D+%282%5E3%29%5E7+-+2%5E%7B15%7D+%3D+2%5E%7B21%7D+-+2%5E%7B15%7D+%3D+)
![= 2^{15}(2^6 - 1) = 2^{15}(64-1) = 2^{15}\cdot63](https://tex.z-dn.net/?f=+%3D+2%5E%7B15%7D%282%5E6+-+1%29+%3D+2%5E%7B15%7D%2864-1%29+%3D+2%5E%7B15%7D%5Ccdot63+)
А 63 делится на 7. Значит 8^7 - 2^15 тоже делится на 7.
6х=2а-4
х=(2а-4)/6 по условию х>1
(2а-4)/6>1 2a-4>6 2a>10 a>5 При а>5 х>1
(2а-4)/4+6х=2а-5(х-1)
2а-4+24х=8а-20х+20
44х=6а+24
х=(6а+24)/44
(6а+24)/44< -1
6a+24 < -44
6a < -68
a <-10 1/3
Так як функція парна то f(x)=f(-x)
тобто f(-18)=f(18)=7