Question

Задание по математике .пожалуста

Answer 1

$1. \\ \frac{6}{ x^{2} -9} : \frac{6}{ (x+3)^{2} } = \frac{6*( x+3)^{2} }{6*( x^{2} -9)} =\frac{(x+3)(x+3)}{(x-3)(x+3)}= \frac{x+3}{x-3} \\ \\ 2. \frac{x+9}{x-3} - \frac{x+3}{x-3} - \frac{3x-3}{x-3} = \frac{x+9-x-3-3x+3}{x-3} = \frac{-3x+9}{x-3} = \\ \\ -\frac{3(x-3)}{x-3} =-3$