1. Ca + 2C4H9COOH = (C4H9COO)2Ca + H2
2. Al(OH)3 + 3C4H9COOH = (C4H9COOH)3Al + 3H2O
3. MgCO3 + 2C4H9COOH = (C4H9COOH)2Mg + H2O + CO2
4. CH3OH + C4H9COOH = C4H9COOCH3 + H2O
Mr(MgCO3) = 24+12+3*16 = 84
W(Mg) = 24/84 = 0.29 =29%
W(C)= 12/84 = 0.14=14%
W(O) = 48/84=0.57 = 57%
20 г Х л
CaCO3=CaO+CO2
100 г 22.4 л
M(CaCO3)=100 г/моль
200/100=x/22.4; x=200×22.4/100=44.8 л CO2
Ba(OH)2+H2SO4--->BASO4+2H2O
m(BaSO4)=300:100*30=90г
M(BaSo4)=137+32+64=233 г\моль
M(Ba(OH)2)=137+34=171 г\моль
n=90:171=0.5 моль
90 г Ba(OH)2--- х BaSO4
171г Ba(OH)2---233 BaSO4
х=90*233:171
х=122,6 г
вроде бы так