=(9а^2-4б^2)/36 ÷(3а+2б)/36=
=(9а^2-4б^2)/(3а+2б)=
=(3а-2б)(3а+2б)/(3а+2б)=
=3а-2б=3×2/3-2×(-1/2)=2+1=3
<span>1<=2-x< 5 1/3
1-2<=-x<5 1/3 -2
-1<=-x<3 1/3
1=>x>-3 1/3
-3-2-1+0+1=-5
</span>
1)a1=-16 a2=8⇒q-a2/a1=-1/2sn=-16*(1-(-1/2)^n)/(1+1/2)=2/3*(-16)*(1-(-1/2)^n)=
-32/3*(1-(-1/2)^n)=-32/3*(1-(-2)^-n)=-32/3+1/3*(-2)^5*(-2)^-n)=-32/3+1/3*(-2)^5-n
2)Sn=b1*(1-(1/4)^n)/(1-1/4)=84
b1*(1-(1/2)^n)*4/3=84
b1*(1-(1/2)^n=84*3/4=63
b1=63/(1-(1/4)^n)
3a(2b + c) + 8b + 4c = 3a(2b + c) + 4(2b + c) = (2b + c)(3a + 4)
5 + 2х = 8 (х - 2)
5 + 2х = 8х - 16
2х - 8х = - 16 - 5
- 6х = - 21
х = - 21/6 = - 3 3/6 = - 3,5
Ответ: - 3,5