Question

Решите уравнение: (2sin(x-p/6)-1)(2tgx+1)=0

Answer 1

(2sin(x-pi/6)-1)(2tgx+1)=0
2sin(x-pi/6)-1=0 &  2tgx+1=0
2sin(x-pi/6)=1        tgx=-1/2
sin(x-pi/6)=1/2       x=-arctg1/2+pik,k∈z
x-pi/6=pi/6+2pik,k∈z
x=pi/3+2pik,k∈z