Решение смотри во вложении.............................
При: x=1,1 y=-0,3
9p²-q²
14x/(x+3y)= 14*1,1) / (1,1+3(-0,3) =1,54 /(1,1-0,9)=1,54/0,2= 7,7
Xxxxxx
a) При: p=2,3 , q=-1,9
9p²-q²=3,3)²-(-1,9)²=3*59-3,61=15,87-3,61=12,26
b) При: p=3/14 , q=5/14
9p²-q² = 9*(3/14)²-(5/14)²=5*9/196 -25/196= 45/196-25/196=
=20/196=5/49
8y³-36y²+54y-27=0
(8y³-27)-<span>(36у</span>²-<span>54y)=0
(2у-3)(4у</span>²+6у+9)-18у(2у-3)=0
<span>(2у-3)(4у</span>²+6у+9-18у)=0
<span>(2у-3)(4у</span>²-12у+9)=0
<span>(2у-3)(2у-3)</span>²=0
<span>(2у-3)</span>³=0
<span>2у-3=0
2у=3
у=3:2
у=1,5
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<span>f(x)=-2x+1
</span><span>y=f(-x)=2x+1
</span>y=|f(x)|=-2x+1;x≤1/2 y=2x-1; x≥1/2
y<span>=f(|x|)=-2|x|+1=-2x+1;x</span>≥0 y=2x+1;x<0