Question

4cos2x+3sin2x=5 Помогите решить пожалуйста

Answer 1

4cos2x+3sin2x=5
-5 + 4cos(2x) + 3sin(2x) = 0
- (cosx - 3sinx)^2 = 0
(cosx - 3sinx)^2 = 0
(cosx - 3sinx) = 0
cosx = 3sinx /cosx ≠ 0
tgx = 1/3
x = arctg(1/3) + πn, n∈Z