Question

3ax-4by+4ay-3bx при а = 1/2 при b =1/3 x= 3 y=-4

Answer 1

3ax-4by+4ay-3bx=(4ay-4by)+ (3ax-3bx)=4y (a-b)+3x (a-b)=
(a-b)(4y+3x)=(1/2-1/3)(4×(-4)+3×3)= (3-2/6)(-16+9)= 1/6×(-7)=-7/6=-1 1/6