<span>Mg</span><span>(</span><span>OH</span><span>)</span><span>2</span><span>+2HCl=MgCl2+2H2O</span>
<span>3Zn(NO3)2+Al2O3=Al2(NO3)2+3ZnO(?)</span>
<span><span>Li2SO4+FeCl2=Li2Fe+Cl2SO4</span></span>
<span><span>P4O10+CaCO3=????</span></span>
<span><span>Li2CO3+FeO2=LiFeO2+CO2</span></span>
<span><span><span>MgSO4</span><span>+</span><span>HNO3</span><span>=MgNO2+H2SO4</span></span></span>
<span><span><span><span>ZnO</span><span>+2HCL=ZnCl2+H2O</span></span></span></span>
Дано:
V(p-pa H2SO4) = 500 мл
ω₁(H2SO4) = 70% или 0,7
ρ(H2SO4) = 1,620 г/см³ = 1,620 г/мл
+V(H2O) = 1 л
Найти:
ω₂(H2SO4)-?
Решение.
m₁(р-ра H2SO4)= 500 мл*1,620 г/мл = 810 г
m(H2SO4) = 810 г*0,7 = 567 г
m(H2O) = 1 л*1 кг/л = 1 кг = 1000 г
m₂(p-pa H2SO4) = 810 г+1000 г = 1810 г
ω₂(H2SO4) = 567 г/1810 г*100% = 31,33%
Ответ: 31,33%
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