24ab+32a-3b= jeśli a=0,3 , b=1 2/3
24(0,3)*(1 2/3)+32*(0,3)-3*(1 2/3)=
= 7,2*5/3+9,6-3*5/3
36/3+9,6-5=12+9,6-5=2,6
<span>x^3-x^2-4x+4=0
</span>x^2(x-1)-4(x-1)=0
(x^2-4)(x-1)=0
(x-2)(x+2)(x-1)=0
x=2, x=-2, x=1
-4sin(3x/4+π/4)>-2√2
sin(3x/4+π/4)<√2/2
3π/4+2πk<3x/4+π/4<9π/4+2πk
π/2+2πk<3x/4<2π+2πk
2π/3+8πk/3<x<3π/2+8πk/3