<span>у=3х-6 k=3;
у=3х+6 k=3;
у=-3х-6 k=-3
Графики f(x)=3x-6 и f(x)=3x+6 - параллельны
f(x)-3x-6 обратна f(x)=3x+6. Её график пересекает графики
</span> f(x)=3x-6 и f(x)=3x+6
Во вложении таблицы и графики
![\lim_{x \to 3} \frac{4x^2-9x-9}{x^3-27}= \lim_{x \to 3} \frac{(4x+3)(x-3)}{(x-3)(x^2+3x+9)} = \lim_{x \to 3} \frac{4x+3}{x^2+3x+9}= \frac{4*3+3}{3^2+3x+9}](https://tex.z-dn.net/?f=+%5Clim_%7Bx+%5Cto+3%7D+%5Cfrac%7B4x%5E2-9x-9%7D%7Bx%5E3-27%7D%3D+++%5Clim_%7Bx+%5Cto+3%7D+%5Cfrac%7B%284x%2B3%29%28x-3%29%7D%7B%28x-3%29%28x%5E2%2B3x%2B9%29%7D+%3D+%5Clim_%7Bx+%5Cto+3%7D+%5Cfrac%7B4x%2B3%7D%7Bx%5E2%2B3x%2B9%7D%3D+%5Cfrac%7B4%2A3%2B3%7D%7B3%5E2%2B3x%2B9%7D++)
![= \frac{15}{27}= \frac{5}{9}](https://tex.z-dn.net/?f=%3D+%5Cfrac%7B15%7D%7B27%7D%3D+%5Cfrac%7B5%7D%7B9%7D++)
В числителе квадратный трёхчлен 4x²-9x-9 разложен на множители:
4x²-9x-9=(*)
D=(-9)²-4*4*(-9)=81+144=225=15²
x=(9-15)/(2*4)=-6/8=-3/4
x=(9+15)/(2*4)=24/8=3
(*)=4(x+(3/4))(x-3)=(4x+3)(x-3)
А знаменатель разложен на множители по формуле разности кубов:
x³-27=x³-3³=(x-3)(x²+3x+9)
Ответ: Звесь нужно доказать равность, значит:
TC=BP
TCO=BPO
CO=BO
TO=PO
2.
BDA=DCA
DO=AC
BO=AO
BDO=CAO
![\left \{ {{ a_{3}=-7 } \atop { a_{2}+ a_{7} =13 }} \right.\\\\ \left \{ {{ a_{1}+2d=-7 } \atop { a_{1}+d+ a_{1} +6d=13 }} \right. \\\\ \left \{ {{ a_{1}+2d=-7 } \atop {2a _{1}+7d=13 }} \right. \\\\- \left \{ {{2a _{1} +4d=-14} \atop {2a _{1}+7d=13 }} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7B+a_%7B3%7D%3D-7+%7D+%5Catop+%7B+a_%7B2%7D%2B+a_%7B7%7D+%3D13+%7D%7D+%5Cright.%5C%5C%5C%5C+%5Cleft+%5C%7B+%7B%7B+a_%7B1%7D%2B2d%3D-7+%7D+%5Catop+%7B+a_%7B1%7D%2Bd%2B+a_%7B1%7D+%2B6d%3D13+%7D%7D+%5Cright.+%5C%5C%5C%5C+%5Cleft+%5C%7B+%7B%7B+a_%7B1%7D%2B2d%3D-7+%7D+%5Catop+%7B2a+_%7B1%7D%2B7d%3D13+%7D%7D+%5Cright.+%5C%5C%5C%5C-+%5Cleft+%5C%7B+%7B%7B2a+_%7B1%7D+%2B4d%3D-14%7D+%5Catop+%7B2a+_%7B1%7D%2B7d%3D13+%7D%7D+%5Cright.++)
______________
- 3d = - 27
d = 9
a₁ = - 7 - 2d = - 7 - 2 * 9 = - 7 - 18 = - 25
X2-3x+9/(х+3)(х2-3х+9) - х2+18/х2+27=х2-3х+9-х2-18/(х+3)х2-3х+9)=-9-3х(х+3)(х2-3х+9)=
=-3(х+3)/(х+3)(х2-3х+9)= 3/х2-3х+9