<span>x(2x+3)(2-x)=0
x</span>₁<span>=0
2x+3=0
2x=-3
x</span>₂=-1.5
2-x=0
x₃=2
Ответ (-1,5; 0; 2)
1)3(2a-1)
2)a2b3(1-ab)
2)6xy(2x-1-4y)
4)(y+5)(x+1)
5)(b-c)(a+1)
6)(b-c)(a-4)
X³-3*2*x²+3*4*x-8+x³+3*2*x²+3*4*x+8=2x³-2x+3
2x³+12*x+12*x=2x<span>³-2x+3
</span>2x³+24x=2x<span>³-2x+3
</span>2x³+24x-2x<span>³+2x-3=0
</span>26x=3
x=3/26
(x^2-1)(x^4+x^2+1)-(x^2-1)(x^2-1)(x^2-1)=(x-1)(x+1)(x^2-x+1)*(x^2+x+1)-(x-1)(x+1)(x-1)^2*(x+1)^2=3x^4-3x^2=3x^2(x-1)(x+1)