C)log(3)24=1+3log(3)2
log(72)3=1/(2+3log(3)2)
log(3)216=3+3log(3)2
log(8)3=1/3log(3)2
log(3)24/log(72)3 - log(3)216/log(8)3=(1+3log(3)2)*(2+3log(3)2)-(3+3log(3)2)*3log(3)2=
=2+3log(3)2+6log(3)2+9log²(3)2-9log(3)2-9log²(3)2=2
e)(lf27+lf12)/(lg2+lg9)=lg324/log18=log(18)324=2
100 умножь на 4 вот тебе и ответ
(а-3)^2 - а(5а-6)=a^2-6a+9-5a^2+6a=-4a^2+9