Ответ:
443₅ = 123₁₀
1000₂ = 8₁₀
Объяснение:
443₅ = 3*5⁰ + 4*5¹ + 4*5² = 123₁₀
1000₂ = 0*2⁰ + 0*2¹ + 0*2² + 1*2³ = 8₁₀
Дано: Решение: N=2^i; 2=2^1; i=1
N=2 I=64*1=64
K=64
Найти
I - ?
var
x: string;
arr: array of char;
begin
readln(x);
arr := x.Split(' ')[1].ToCharArray();
System.Array.Reverse(arr);
writeln(length(arr), ' ', new string(arr));
end.
---------------------------------------
var
c: array of integer := (10, 20, 10, 30, 40, 50, 55, 1, 5, 9, 4, 3, 2);
r, q, s: real;
i, a, b: byte;
begin
q := 1;
i := 1;
r := c.Min();
while (i < length(c)) do
begin
q *= c[i];
i += 2;
end;
readln(a, b);
s := b - a - 1;
writeln('T = ', (R / Q + 1) + S);
end.
-----------------------------
const
k = 5;
p = 5;
var
f: array [1..k, 1..p] of string;
o: real;
df: byte;
begin
for i: byte := 1 to k do
begin
for j: byte := 1 to p do
begin
f[i, j] := random(10, 99).ToString();
write(f[i, j]:3);
if (j >= 7 - i) then
begin
o += integer.Parse(f[i, j]);
df += 1;
f[i, j] := '██';
end;
end;
writeln();
end;
writeln();
for i: byte := 1 to k do
begin
for j: byte := 1 to p do
write(f[i, j]:3);
writeln();
end;
writeln(o / df);
end.
Python 3.7.0
import random
pr = 1
for i in range(5):
x = round(random.uniform(1, 1.3), 2)
pr *= x
print(x)
srgeom = round(pr ** (1 / 5), 2)
print("Среднее геометрическое чисел: " + str(srgeom))
